# The stem in a stem-leaf diagram

GRABMYESSAY.COM OFFERS TO EVALUATE SAMPLES OF VARIOUS TYPES OF PAPERS
High School ・Statistics ・MLA

The trunk in the trunk diagram gives the right digit of the number you want and the leaf gives the right digit of the number you want. To achieve the appropriate value, the leaf unit must be multiplied by each leaf value. In our example, the lowest value is given by the least value of stem and leaf, which are 5 and 2. So, the smallest value is 5(2 × 0.1) = 5.2. Proceeding similar way, the largest number may be found from the largest (lowermost) value of stem and the largest value of the leaf. This gives 8 and 9 and the largest number becomes 8(9 × 0.1) = 8.9.
Problem 6
We have 28 numbers (as can be found from the leaf values). So, each quartile will be composed of 7 values. The first quartile be given by first 7 values constructed from the stem and leaf.
The average of 7th and 8th values will give the first quartile value. Thus, the average of 6.1 and 6.4 is 6.25, which is the required answer.
Problem 9
Sample mean may be found by adding all numbers and then dividing the by the number of terms. Here,
21 + 38 + 35 + 31 + 28 + 22 + 25 + 32 + 24 + 35 + 27+ 30 = 348
Total number of terms = 12
Average = 348/12 = 29.0
Problem 10
Sample median may be found by arranging the terms in ascending order and finding the value of the middle term.
21, 22, 24, 25, 27, 28, 30, 31, 32, 35, 35, 38
Here, total number of terms is 12; middle terms are 6th and 7th terms: 28 and 30. The average of the middle terms = (28+30)/2 = 58/2 = 29.0
Problem 11
Sample standard deviation may be found by
Subtracting the average value of the sample from each term
Taking the sum of squares of all differences,
Dividing the sum by the number of terms less one (here, 12-1 =11)
Then taking square root of the result.
Standard Deviation = √(((21–29)^2+(22–29)^2+(24–29)^2+(25–29)^2+(27–29)^2+(28–29)^2+(30–29)^2+(31–29)^2+(32–29)^2+(35–29)^2+(35–29)^2+(38–29)^2)/11)
= 5.44
Problem 12
Coefficient of variation is found by taking percentage of the quotient of standard deviation by mean.
Coefficient of variation = (Standard Deviation )/(Mean ) × 100%
= 5.44/29 × 100%
= 18.8%
Problem 16
z-score = (x–μ)/σ; here, mean, μ = 29 and standard deviation, σ = 5.44
= (38–29)/5.44
= 1.65
Problem 20
Slope, b1 = (n∑▒tY–(∑▒〖Y)(∑▒〖t)〗〗)/(n∑▒t^2 –(∑▒〖t)〗^2 )
Here, ∑▒t = 1 + 2 + 3 + 4 +5 = 15
∑▒t^2 = 12 +22 +32 +42 +52 = 1 +4 +9 +16 +25 = 55
= (5×1104.2–335.7×15)/(5×55 –〖15〗^2 ) = 9.71
Problem 21
Intercept, b0 = (∑▒Y)/n – b1 (∑▒t)/n
= (1104.2)/5 – 9.71×15/5
= 38.01
Problem 22
The trend equation, Y’ = b0 + b1t
= 38.01 + 9.71t
For 2006, t = 6; the forecasted number of visitor can be found by putting t = 6 in the trend equation.
Y’ = 38.01 + 9.71 × 6 = 96.03
PRACTICE EXAM 1-B
Problem 6
The stem in a stem-leaf diagram gives the rightmost digit of the desired number and the leaf will give the leftmost digit of the desired number. The leaf unit must be multiplied with each leaf value to get the required value.
In our example, the lowest value is given by the least value of stem and leaf, which are 2 and 2. So, the smallest value is 2(2 × 10) = 220. Total number of leaves before 4 in the stem row 4 are 17.
Problem 10
Sample mean may be found by adding all numbers and then dividing the by the number of terms. Here,
39 + 13 + 20 + 5 + 29 + 3 + 7 + 11 + 8 + 9 + 35 + 17 + 5 + 40 + 44 = 285
Total number of terms = 15
Average = 285/15 = 19.0
Problem 11
Sample median may be found by arranging the terms in ascending order and finding the value of the middle term.
3, 5, 5, 7, 8, 9, 11, 13, 17, 20, 29, 35, 39, 40, 44
The middle term of 15 terms is the 8th term, which is 13.
Problem 12
See problem 11 of exam 1-A
Problem 16
See problem 16 of exam 1-A
Problem 19
Problem 20
See problem 21 of exam 1-A
Problem 21
See problem 22 of exam 1-A
Problem 22
Running total is calculated by adding all quarter values corresponding to each year.
The first running total corresponds to first year 2003:
175 + 167 + 140 + 135 = 617
The first running total corresponds to first year 2004:
180 + 175 + 150 + 142 = 647
PRACTICE EXAM 1-C
Problem 8
See problem 5 of exam 1-A
Problem 9
The values are 410 to 960, which gives a range of (960–410) = 550.
Problem 10
See problem 10 of exam 1-B
Problem 11
See problem 11 of exam 1-B
Problem 12
See problem 12 of exam 1-B
Problem 15
See problem 16 of exam 1-B
Problem 19
See problem 20 of exam 1-A
Problem 20
See problem 21 of exam 1-A
Problem 21
See problem 22 of exam 1-A
PRACTICE EXAM 1-D
Problem 4
See problem 5 of exam 1-A
Problem 8
See problem 9 of exam 1-A
Problem 9
See problem 10 of exam 1-A
Problem 10
See problem 11 of exam 1-A
Problem 11
See problem 12 of exam 1-A
Problem 13
See problem 16 of exam 1-A
Problem 17
See problem 20 of exam 1-A
Problem 18
See problem 21 of exam 1-A
Problem 19
See problem 22 of exam 1-A
PRACTICE EXAM 1-E
Problem 6
See problem 5 of exam 1-A
Problem 9
See problem 9 of exam 1-A
Problem 10
See problem 10 of exam 1-A

Problem 11

See problem 11 of exam 1-A

Problem 12

See problem 12 of exam 1-A

Problem 15

See problem 16 of exam 1-A

Problem 19

See problem 20 of exam 1-A

Problem 20

See problem 21 of exam 1-A

Problem 21

See problem 22 of exam 1-A

Get a price
Urgency
Pages *275 words
Total price
Related Samples
Related Categories

### Prices that are easy on your wallet

Our experts are ready to do an excellent job starting at \$14.99 per page

What Clients Say About Us
Our Customers Rated UsGreat
4.8
Out of 5 Based on 246 Reviews
I experienced difficult times trying to complete huge number of assignments to my university at the same time and you, guys, literally saved me. Everything was done in time and on the highest level! I really appreciate your help.
Edward,
Essay, History, 12 pages, 7 days, Master's
First time when I placed an order with you, I just lacked time to do all the homework and it was a lot going on in my family. But today I’m doing it sometimes just for fun – I really enjoy communicating with your Customer Support members and just letting myself being a bit lazy
Yuong Lo Mui,
Literature review, IT, 17 pages, 4 days, Master's
My GPA is 4.0 and I’ve always been doing everything myself, but there is a class which I was about to fail thus my GPA would decrease first time in so many years. I ordered few assignments to be completed with GrabMyEssay.com and you did a great job! Thanks to you I still remain one of the best students on campus.
Rosalinda,
Essay, Politics, 8 pages, 5 days, Junior
I am not used to such services and I usually write all the papers by myself. But this time I got in a very difficult situation and had to order my paper on this website. To my surprise it appeared to be quite good. Thank you, it is really nice service. Think I'll get back to you soon!
Jeremy,
Thesis, Management, 34 pages, 14 days, Master's
I am on my maternity leave now, so I spend a lot of time at home taking care of my little son. I’ve decided to get one more higher education degree while I’m spending so much time at home and applied for distance learning in one online college. But caring a baby takes even more time then I excepted so I’m the way too busy to write the complicated masters level research works, but GrabMyEssay.com is so-so-so cool! Thank you for that you exist! I don’t know what I would do without you all!
Karen,
Essay, Education, 15 pages, 8 days, Master's
I am studying and working at the same time and it is difficult to cope with university assignments as I am very tired after the work day. You service is a salvation for me as it helps to do everything on time. I am really happy about it. Wish you everything the best! Especially my lovely writer 109!
Desmond,
Coursework, Religion, 11 pages, 7 days, Master's

### We at GrabMyEssay.com

work according to the General Data Protection Regulation (GDPR), which means you have the control over your personal data. All payment transactions go through a secure online payment system, thus your Billing information is not stored, saved or available to the Company in any way. Additionally, we guarantee confidentiality and anonymity all throughout your cooperation with our Company.